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Liquid water freezes at 273K under exter...

Liquid water freezes at 273K under external pressure of 1 atm. The process is at equilibrium `H_(2)O (l) hArr H_(2)O (s)` at 273 K & 1 atm. However it was required to calculate the thermodynamic parameters of the fusion process occuring at same pressure & different temperature.Using the following data, answer the question that follow. `d_("ice") = 0.9` gm/cc, `d_(H_(2)O(l))` = 1 gm//c, `C_(P) [H_(2)O(s))] = 36.4 JK^(-1) mol^(-1)`
`C_(P) [H_(2)O(l)] = 75.3 JK^(-1) mol^(-1), Delta H_("fusion") = 6008.2 J mol^(-1)`
''`DeltaS_("fusion")`'' at 263 K & 1 atm will be

A

`22.01 JK^(-1) mol^(-1)`

B

`22.84 JK^(-1) mol^(-1)`

C

`21.36 JK^(-1) mol^(-1)`

D

`20.557 KJ^(-1) mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`Delta S_("fusion")` at 263K `= (Delta H_("fusion") " at " 263)/(263) = 21.365 Jk^(-1) "mole"^(-1)`
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