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(IE)1 and (IE)2 of Mg((g)) are 740, 1540...

`(IE)_1` and `(IE)_2` of `Mg_((g))` are 740, 1540 kJ `mol^(-1)` . Calculate percentage of `Mg_((g))^(+)` and `Mg_((g))^(2+)` if 1 g of `Mg_((s))` absorbs 50.0 kJ of energy.

A

`% Mg^(+) = 50 % %Mg^(+2) = 50 %`

B

`% Mg^(+) = 70.13 % %Mg^(+2) = 25 %`

C

`%Mg^(+) = 75 % %Mg^(+2) = 25 %`

D

`% Mg^(+) = 60 % %Mg^(+2) = 40 %`

Text Solution

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The correct Answer is:
B
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AAKASH SERIES-PERIODIC TABLE-OBJECTIVE EXERCISE -3
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