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One mole of compound AB reacts with one ...

One mole of compound AB reacts with one mole of a compound CD according to the equation `AB_((g)) + CD_((g)) hArr AD_((g)) + CB_((g))` . When equilibrium had been established it was found that 3/4 mole of reactants AB and CD had been converted to AD and CB . There is no change in volume . The equilibrium constant for the reaction is

A

`9//16`

B

`1//9`

C

`16//9`

D

9

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The correct Answer is:
D
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