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Two oxide of metal M have 27.6% and 30% ...

Two oxide of metal M have `27.6%` and `30%` oxygen by weight. If the formula of the first oxide is `M_(3)O_(4)` what is the formula of second oxide?

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Oxide (A) : Oxygen `27.6%,4.O.` atoms
Metal `72.4%,3.M.` atoms
Oxide (B) : Oxygen `30%` , Metal `70%`
`"Number of .O. atoms "=(30)/(27.6)xx4=4.35`
Number of .N. atoms `=(70)/(72.4)xx3=2.9`
`"Ratio of M and O atoms in oxide B = 2.9 : 4.35 = 2 : 3"`
`"Formula of the second oxide is "M_(2)O_(3)`
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