3 litres each of Nitrogen and Hydrogen measured at STP are allowed to react together. Find the volumes of the gases after the reaction and also the weight of Ammonia formed in the reaction.

Explanation

Balanced equation is
`underset("1 vol")(N_(2(g)))+underset("3 vol")(3H_(2)(g))rarrunderset("2 vol")(2NH_(3(g)))`
Ratio fo volume of `N_(2), H_(2) and NH_(3)` is `1:3:2`
3 litres of `H_(2)` reacts with 1 litres of `N_(2)` and forms 2 litres of `NH_(3)`. Hence volumes of `N_(2) and H_(2)` after the reaction are 2 litres (3 - 1) and .0. litres respectively.
Weight of 22.4 lit of `NH_(3)` at STP = 17g
`"Weight of 2 lit of "NH_(3)" at STP"=(17xx2)/(22.4)=1.517" gram"`