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Combustion of 0.202 g of a carbon compou...

Combustion of 0.202 g of a carbon compound gave 0.361 g of carbon dioxide and 0.147g of water. Determine the empirical formula of the compound. 

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`%C=(0.361xx12xx100)/(0.202xx44)=48.76%`
`%H=(0.147xx2xx100)/(0.202xx18)= 8.07%`
`%O=100-56.83=43.17`
`C:H:O=(48.76)/(12):(8.07)/(1):(43.17)/(16)`
`=4.06:8.07:2.7=3:6:2`T
he empirical formula of the compound is `C_(3)H_(6)O_(2)`.
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