The empirical formula an organic substance is `CH_(2)O`. If `3 xx 10^(22)` molecules of the substance has a mass of one sixth of mass of one gram mole of water, find the hybridisation of carbon atoms in the compound. 

Explanation

One mole water `= 18 g`
`3xx10^(22)` molecules of compound `6xx10^(23)` molecules of compound`= ?`
Molar mass of compound is
`(6xx10^(23))/(3xx10^(2))xx3=60g"                   "n=(60)/(30)=2`
Molecular formula is `C_(2)H_(4)O_(2)=CH_(3)-overset(O)overset(||)C-OH`
Hybridisation of .C. atoms is `sp^(2),sp^(3)`