One mole of hydrazine loses 10 moles of electrons. If all the nitrogen content is present in the product, what is the oxidation number of nitrogen in the product? 

Explanation

Chemical formula of hydrazine is `H_(2)N-NH_(2)`
Oxidation number of each Nis `-2`
`2xx-2overset("loss of "10e^(-))rarr?`
or `1xx-2overset("loss of "5e^(-))rarr?`
Oxidation number of N in the product `= -2-(-5)=+3`.