Calculate the percent weight loss suffered by sodium bicarbonate on strong heating? 

Explanation

On strong heating sodium bicarbonate decomposes and loses carbondioxide and water.
`2NaHCO_(3)rarr Na_(2)CO_(3)+H_(2)O+CO_(2)`
2 moles of `NaHCO_(3)-=1` mole of `CO_(2) + 1` mole of `H_(2)O`
`(2xx84)` grams of `NaHCO_(3)-=(44+18)` grams weight loss
100 grams of `NaHCO_(3)-= ?`
The percent weight loss suffered by sodium carbonate on `=(100)/(2xx84)xx62=36.9%`