What volume of carbonmonoxide at 2 atm and `273^(@)C` is required in order to produce 5.6 grams of metal by the reduction of ferric oxide? 

Explanation

Reduction of ferric oxide with carbonmonoxide gives iron metal.
`Fe_(2)O_(3)+3COrarr3CO_(2)+2Fe`
2 moles of `Fe -= 3` moles of CO
56 grams of `Fe -= 33.6` L of CO at STP
5.6 grams of `Fe -= 3.36` lit of CO at STP
The volume of CO required at STP = 33.6 L
`{:("STP conditions","Given conditions"),(P_(1)=1atm,P_(2)=2atm),(T_(1)=273K,T_(2)=2xx273K),(V_(1)=3.36L,V_(2)=?):}`
`V_(2)=(P_(1)V_(1))/(T_(1))xx(T_(2))/(P_(2))=(1xx3.36xx2xx273)/(273xx2)=3.36L`