What is the volume of ammonia obtained starting from 2 L of nitrogen, if the conversion  is only `6%` efficient in the given conditions? 

Explanation

Conversion of nitrogen to ammonia is given as
`N_(2)+3H_(2)rarr 2NH_(3)`
1 mole of `N_(2) = 2` moles of `NH_(3)`
1 volume of `N_(2) = 2` volumes of `NH_(3)`
Volume of ammonia with `100%` efficient conversion of 2 L nitrogen = 4 L
Volume of ammonia with `6%` efficient conversion of the reaction `=(6xx4)/(100)=0.24L`