Calculate the weight of calcium calcium carbonate required to produce carbondioxide that is sufficient for conversion of one decimole sodium carbonate to sodium bicarbonate.

Explanation

Step 1 : Regarding the requirement of carbon - dioxide :
The balanced equation for conversion of sodium carbonate to sodium bicarbonate is
`Na_(2)CO_(3)+H_(2)O+CO_(2)rarr2NaHCO_(3)`
Decimole = 0.1 mole
`"1 mole of "Na_(2)CO_(3)-="1 mole of "CO_(2)`
Carbondioxide required for 0.1 mole of `Na_(2)OC_(3)=0.1` mole (or 4.4 grams)
Step 2 : Regarding the requirement of calcium carbonate :
The balanced equation for the decomposition of calcium carbonate is
`CaCO_(3)rarrCaO+CO_(2)`
`"1 mole of "CO_(2)-="1 mole of "CaCO_(3)`
`"44 grams of "CO_(2)-=100" grams of "CaCO_(3)`
The weight of calcium carbonate to produce the required 4.4 grms carbondioxide `=(100)/(44)xx4.4=10" grams"`