Calculate the volume of `O_(2)` at STP required to burn completely 70 ml of acetylene.

Explanation

Combustion of acetylene is given as
`2C_(2)H_(2)+5O_(2)rarr4CO_(2)+2H_(2)O`
`"2 mole of "C_(2)H_(2)-="5 moles of "O_(2)`
`"2 volumes of "C_(2)H_(2)=5"volumes of "O_(2)`
`"2 mL of "C_(2)H_(2)="5 mL of "O_(2)`
Volume of oxygen required to burn 70 mL of acetylene `=70xx(5)/(2)="175 mL"`