In a gas phase reaction, 50 kg of nitrogen and 10 g of hydrogen are mixed to produce ammonia. Identify the limiting reagent. Calculate the maximum amount of ammonia produced.

Explanation

The gaseous phase chemical equation for the production of ammonia is given as
`N_(2)+3H_(2)rarr2NH_(3)`
1 mole of `N_(2)-=` moles of `H_(2)`
`"28 kg of "N_(2)=(2xx3)" kg of "H_(2)`
`"46.67 kg of "N_(2)="10 kg of "H_(2)`
`"50 kg of "N_(2)="10.71 kg of "H_(2)`
Hence, hydrogen is the limiting reagent,
`"3 moles of "H_(2)="2 moles of "NH_(3)`
`(3xx2)" kg of "H_(2)=(2xx17)" kg of "NH_(3)`
`"10 kg of "H_(2)=?`
Maximum amount of ammonia produced is
`=(2xx17xx10)/(3xx2)=56.6kg`