100 mL of each acetylene and oxygen are mixed. The mixture is strongly heated to complete the reaction and colled back to room temperature. What is the maximum volume of carbondioxide obtained. Why?

Explanation

The stoichiometric equation for burning of acetylene is given as
`2C_(2)H_(2)+5O_(2)rarr4CO_(2)+2H_(2)O`
`"2 moles of "C_(2)H_(2)="5 moles of "O_(2)`
`"2 volumes of "C_(2)H_(2)=5" volumes of "O_(2)`
`"100 mL of "C_(2)H_(2)=250mL" of "O_(2)`
`"40 mL of "C_(2)H_(2)=100 mL " of "O_(2)`
Hence the limiting reagent is oxygen
`"5 moles of "O_(2)="4 moles of "CO_(2)`
`"5 volumes of "O_(2)="4 volumes of "CO_(2)`
`"100 mL of "O_(2)=?`
The maximum volume of `CO_(2)` formed `=100xx(4)/(5)="80 mL"`
This is because no sufficient `O_(2)` is available.