A jug contains 2L of milk. Calculate the volume of the milk in `m^(3)`.

Explanation

`"1 L "="1000 cm"^(3) and 1m=100 cm`
`(1m)/(100cm)=1=(100cm)/(1m)`
To get `m^(3)` from the above unit factors, the first unit factor is taken and it is cubed.
`((1m)/(100m))^(3)rArr(1m^(3))/(10^(6)cm^(3))=(1)^(3)=1`
Now `2L=2xx1000cm^(3)`
The above is mltiplied by the unit factor
`2xx1000cn^(3)xx(1m^(3))/(10^(6)cm^(3))=(2m^(3))/(10^(3))=2xx10^(-3)m^(3)`