A container of just 10cc has `2.69 xx 10^20` gas molecules at `0^@C`. What is the pressure exerted?

Explanation

Number of moles of the gas = `(2.69 xx 10^20)/(6.022 xx 10^(23)) = 4.47 xx 10^(-4)`
Pressure (P) exerted by gas molecules :
`P = (nRT)/V = (4.47 xx 10^(-4) xx 82.1 xx273)/10 = 1 atm`.