A vessel of irregular shape has a volume 'V'. It is first evacuated and coupled with a vessel of 4L capacity at `35^@C` and 10 atm pressure. If the final pressure in both the vessels is 3atm, calculate the volume V.

Explanation

`{:("Unknown vessel ","Known vessel "),(V_1 = VL","V_2 = 4L),(P_1 = 0 "atm", P_2 = 10 "atm"):}`
The average pressure (P) of the mixture of the gases from two vessels = P =
`3= (0 xx V + 10 xx 4)/(V + 4) = 40/(V + 4)` Solving, V=9.3L
The volume of the given vessel of irregular shape is 9.3L.