What is the pressure exerted by `10^(23)` gas molecules, each molecule of mass `10^(-23)`g, present in a container of volume one L and RMS speed of `1000 m s^(-1)`?

Explanation

Kinetic gas equation `PV = 1/3 mn C^2`
Pressure of the gas (P)
`P = (mnC^2)/(3V) = (10^(-23) xx 10^(23) xx 10^(10))/(3 xx 1000) = 3.33 xx 10^6 "dy cm"^(-2)` .