Home
Class 11
CHEMISTRY
The average K.E. of one mole of an ideal...

The average K.E. of one mole of an ideal gas in calories is equal to 

A

3 times of its absolute temp

B

2 times of its absolute temp

C

4 times of its absolute temp

D

2/3 times of its absolute temp

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • STATES OF MATTER

    AAKASH SERIES|Exercise OBJECTIVE EXERCISE - 1 (TYPES OF VELOCITIES)|17 Videos

  • STATES OF MATTER

    AAKASH SERIES|Exercise OBJECTIVE EXERCISE - 1 (VAN DER WAAL EQUATIONS)|14 Videos

  • STATES OF MATTER

    AAKASH SERIES|Exercise OBJECTIVE EXERCISE - 1 (GRAHAM.S LAW)|21 Videos

  • SATURATED HYDROCARBONS

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|10 Videos

  • STOICHIOMETRY

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|59 Videos

Similar Questions

Explore conceptually related problems

Find the kinetic energy of 2 moles of an ideal gas in calories at 27^@C

The average kinetic energy of one molecule of an ideal gas at 27^@ C and 1 atm pressure is

The internal pressure loss of one mole of vander Waal gas over an ideal gas is not equal to

The average momentum of a molecule in an ideal gas depends on

Prove that the average kinetic energy of a molecule of an ideal gas is directly proportional to the absolute temperature of the gas.

The average K.E. of an ideal gas per molecule in SI units at 25^@ C is