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Write the position isomers of (a) C(3)H(...

Write the position isomers of (a) `C_(3)H_(6)Cl_(2)` (b) `C_(3) H_(5) Cl`

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(a) The number of position isomers for the formula `C_(3)H_(6)Cl_(2)` is four
(1) `CH_(3) - CH_(2) - CHCl_(2)` 1,1-Dichloroporpane (2) `CH_(3) - C Cl_(2) - CH_(3)` 2,2-Dichloropropane
(3) `CH_(3) - CHCl - CH_(2)Cl` 1, 2-Dichloropropane (4) `CH_(2)Cl- CH_(2) - CH_(2)Cl` 1, 3-Dichloropropane
(b) The number of position isomers for the formula `C_(3)H_(5)Cl` is three.
(1) `CH_(2) = CH-CH_(2)Cl` 3-Chloropropene (2) `CH_(2) = C Cl- CH_(3)` 2-Chloropropene (3) `CHCl= CH- CH_(3)` 1-Chloropropene
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