0.2g of an organic compound on analysis give 0.147g of carbondioxide, 0.12 g of water and 74.6 c,c of nitrogen at S.T.P. Calculate the weight percentages of constituents.

Explanation

Weight of compound = W= 0.2g
Weight of `CO_(2) = W_(1) = 0.147g`
Weight of `H_(2)O = W_(2) = 0.12g`
Volume of `N_(2)` at STP= 74.6 c.c
% of Carbon `= (W_(1) xx 12 xx 100)/(W xx 44) = (0.147 xx 12 xx 100)/(0.2 xx 44) = 20.04%`
% of Hydrogen `= (W_(2) xx 2 xx 100)/(W xx 18) = (0.12 xx 2 xx 100)/(0.2 xx 18) = 6.66%`
% of Nitrogen `=(V_(2) xx 28 xx 100)/(W xx 22400) = (74.6)/(8 xx 0.2) = 46.63%`
Remaining is oxygen
% of Oxygen `=100-(%C + %H + %N)`
`=100 -73.33 = 26.67%`