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5 kg of water contain 24 mg of MgSO4 an...

5 kg of water contain 24 mg of `MgSO_4` and 32.4 mg of `Ca(HCO_3)_2` . The total hardness of water is

A

4 PPM

B

6PPM

C

8 PPM

D

7 PPM

Text Solution

Verified by Experts

The correct Answer is:
C
`MgSO_4 = (24 xx 10^(-3))/(5 xx 10^(3)) xx 10^6 = 4.8 p pm`
4.8 gm in `5 xx 10^3` gm of water
`Ca(HCO_3)_2 = (32 .4 xx 10^(-3))/(5 xx 10^(-3)) xx 10^6 = 6.48 p pm`
6.48 gm in `5 xx 10^3` gm of water
permanent hardness `= 4.8 xx 100/120 = 4ppm`
temperory hardness `= 6.48 xx 100/120 = 4ppm`
total hardness = permanent + temperory
` = 4 + 4 = 8 `ppm
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