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Electrolysis of 50% H.SO, produces...

Electrolysis of 50% H.SO, produces

A

`H_2S_2O_8` at anode

B

`H_2SO_5` at cathode

C

`H_2` at anode

D

`H_2O_2` at anode & Cathode

Text Solution

Verified by Experts

The correct Answer is:
A
At anode `2HSO_4^(-) to H_2S_2 O_8 + 2e^(o.)`
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