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When BiCl3 is dissolved in excess of D2...

When `BiCl_3` is dissolved in excess of `D_2O`, the product formed is

A

`Bi(OD)_3`

B

`BiOCl`

C

`Bi(OD)_2`

D

`BiD_3`

Text Solution

Verified by Experts

The correct Answer is:
B
`BiCl_3 + D_2O to BiOCl + 2DCl`
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