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What is the degree of hardness of a sample of water containing 6 mg of `MgSO_4` (molecular mass 120) per kg of water ?

Text Solution

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The correct Answer is:
5
6 mg of `MgSO_4` present in `10^3` g of water
`10^6` g water will contain
` =6000 mg` of `MgSO_4`
`120 g "of " MgSO_4` = 100 g of `CaCO_3`
So, 6 g of `MgSO_4 = 100/120 xx 6 = 5g " of " CaCO_3`, i.e., Hardness = 5 ppm
`LiH + H_2O to LiOH + H_2`
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