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Pure H(2)O(2) is not very stable and de...

Pure `H_(2)O_(2)` is not very stable and decomposes in the presence of light or on standing or heating
`overset((-1))(H_(2)O_(2l))+overset((2-)) (H_(2)O_((l)))+overset((0))(O_(2(g)))`
The oxidation state of oxygen in `H_(2)O_(2)` is 1 it is oxidistion state of zero in `O_(2)` and is reduced to an oxidation state of -2 in `H_(2)O`. Thus, this decomposition is an example of auto oxidation reduction reaction or disproportionation reaction.
30-volume, hydrogen peroxide means

A

30% of `H_2O_2` by volume

B

30g of `H_2O_2` solution contains 1g of `H_2O`

C

`1 cm^3` of solution liberates `30 cm^3` of dioxygen gas at STP

D

`30cm^3` of the solution contains one mole of `H_2O_2`

Text Solution

Verified by Experts

The correct Answer is:
C
30 -volume,hydrogen peroxide means `1 cm^3` of solution liberates `30 cm^3` of dioxygen gas at STP
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