'H(2)O(2)' ---> 2H + O(2) + 2e The above...

'H_(2)O_(2)' ---> 2H + O_(2) + 2e The above equation represents the following nature `H_(2)O_(2)`

A

Acidic

B

Oxidising

C

Reducing

D

Bleaching

Verified by Experts

The correct Answer is:

C

Loosing og `e^(o.)` and called oxidation. `H_2O_2 `is called reducing agent

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