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Hydrogen peroxide is ionise as : H(2)O(2...

Hydrogen peroxide is ionise as `: H_(2)O_(2) hArr H^(+)+HO_(2)^(-)`. If `p^(h) of H_(2)O_(2)` is `5.91` at `25^(@)C` the ionic product of `H_(2)O_(2)` is

A

`1.51 xx 10^(-12)`

B

`1.15 xx 10^(-12)`

C

`1 xx 10^(-14)`

D

`1.1 xx 10^(-12)`

Text Solution

Verified by Experts

The correct Answer is:
A
`[H^(+)]" at" 25^@C =10^(-5.91) = 1.23 xx 10^(-6)M`
`[H^(+)] " at" 25^@C = 10^(-5.91) = 1.23 xx 10^(-6) M`
`K = [H^(+)][HO_2^(-)] = [1.23 xx 10^(-6)]^2 = 1.51 xx 10^(-12)`
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