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10 ml of H2O2 solution on decomposition...

10 ml of `H_2O_2` solution on decomposition liberated 200ml of `O_2` at STP. Then the weight/volume percentage of that `H_2O_2` solution is

A

112 mL

B

336 mL

C

200 mL

D

224 mL

Text Solution

Verified by Experts

The correct Answer is:
A
Normality of 20 volume `H_2O_2= 20 /5.6 N`
`:. 20/5.6 xx V = 2 xx 200 or V = 112 mL`
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