Home
Class 11
CHEMISTRY
In the synthesis of sodium carbonate, th...

In the synthesis of sodium carbonate, the recovery of ammonia is done by treating NH CI with `Ca(OH)_(2)`. The by-product obtained in this process is

A

`CaCl_(2)`

B

NaCl

C

NaOH

D

`NaHCO_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A

`CaCI_(2)` is the by product in solvay process
Promotional Banner

Similar Questions

Explore conceptually related problems

A solution of sodium carbonate reacts with Ca(OH)_2 to give

Jaswanth brought Ca(OH)_2 solution to check the product in the reaction

Electrolysis is an important technique for extraction of metals and each low of the solution needs a minimum voltage to get discharged and this value is expressed in terms of discharge potential. For some metal ions the discharge potentials follow the order give below : Li^(+) gt K^(+) gt Ca^(2+) gt Na^(+) gt Mg^(2+) gt Al^(3+) gt Zn^(2+) gt Fe^(2+) gt Ni^(2+) gt H_(3)O^(+) gt Cu^(2+) gt Hg_(2)^(2+) gt Ag^(+) gt Au^(3+) For some anions the discharge potentials are in the order: SO_(4)^(2-) gt NO_(3)^(-) gt OH^(-) gt Br^(-) gt I^(-) A mixture containing chlorides of sodium, calcium and zinc is electrolysed in presence of water The product obtained at cathode will be

Give the structure and IUPAC name of product . Obtained when acetone is treated with Ba(OH)_2

Solid sodium hydroxide is reached with carbon monoxide under pressure , what is the product obtained ?

If the following compound is treated with pd/c in excess of H_2 gas, how may stereoisomer's of the product will be obtained?

If the following compound is treated with pd/C in excess of H_2 gas, how many stereoisomers of the product will be obtained?

If the following compound is treated with pd/C in excess of H_2 gas, how many stereoisomers of the product will be obtained?