60^(@)" below the "x" -axis in the fourth quadrant.The sum "bar(A)+bar(B)" is a vec "

Vector vec(A) is 2 cm long and is 60^(@) above the x-axis in the first quadrant. Vactor vec(B) is 2 cm long and is 60^(@) below the x-axis in the fourth quadrant. The sum vec(A)+vec(B) is a vector of magnitudes

Vector vec(A) is 2 cm long and is 60^(@) above the x-axis in the first quadrant. Vactor vec(B) is 2 cm long and is 60^(@) below the x-axis in the fourth quadrant. The sum vec(A)+vec(B) is a vector of magnitudes

vec(A) and vec(B) are two vectors such that vec(A) is 2 m long and is 60^(@) above the x - axis in the first quadrant vec(B) is 2 m long and is 60^(@) below the x - axis in the fourth quadrant . Draw diagram to show vec(a) + vec(B) , vec(A) - vec(B) and vec(B) -vec(A) (b) What is the magnitude and direction of vec(A) + vec(B) , vec(A) - vec(B) and vec(B) - vec(A)

Vector vecA is 2 cm long and is 60° above the x - axis in the first quadrant, vector vecB is 2cm long and is 60° below the x - axis in the fourth quadrant. Find vecA + vecB

Vector vecA is 2 cm long and is 60° above the x - axis in the first quadrant, vector vecB is 2cm long and is 60° below the x - axis in the fourth quadrant. Find vecA + vecB

If bar(a) is perpendicular to bar(b) then bar(a)*bar(b) is

If |vec a|=2,|vec b|=sqrt(3) and (bar(a),bar(b))=30^(@) then the angle between the vectors bar(b) and bar(a)-bar(b) is