In `SHM` at the equilibrium position
(i) displacement is minimum
(ii) acceleration is zero
(iii) velocity is maximum
(iv) potential energy is maximum

In S.H.M. at the equilibrium position a) Amplitude is minimum b) acceleration is zero c) Velocity is maximum d) P.E is maximum

Where is maximum acceleration and zero velocity of a particle axecuting SHM?

Acceleration -time graph of a particel executing SHM is as shown in fig. Then (i) displacement of particle at 1 is -ve (ii) velocity of particel at 2 is +ve (iii) potential enegry of particel at 3 is maximum (iv) speed of particel at 4 is decreasing.

Show analytically that in S.H.M. the acceleration is zero when the velocity is maximum and that the velocity is zero when acceleration is maximum.

Acceleration - time graph of a particle executing S.H.M is as shown in fig. Then i) displacement of particle at 1 is - ve ii) velocity of particle at 2 is + ve iii) potential energy of particle at 3 is maximum iv) speed of particle at 4 is decreasing.

At which point of projectile motion (i) potential energy is maxumum (ii0 kinetec eneragy is maximum (iii) total vechnical energy is maximum.

For a particle in S.H.M. if the maximum acceleration is a and maximum velocity is v then amplitude is

A particle executes SHM on a straight line path. The amplitude of oscillation is 2 cm. When the displacement of the particle from the mean position is 1 cm, the magnitude of its acceleration is equal to that of its velocity. Find the time period, maximum velocity and maximum acceleration of SHM.