सिद्ध कीजिए की `(cos 2B-cos2A)/(sin 2B+sin 2A)= tan (A-B)`

(cos2B-cos2A)/(sin2B+sin2A)=tan(AB)

(cos 2B - cos 2 A)/( sin 2 A + sin 2 B) = tan (A -B).

Prove that ((sin 2A -sin 2B)/(cos2A + cos 2B))^(n) + ((cos 2A - Cos 2B)/(sin 2A + sin 2B))^(n) = 2 tan^(n) (A-B) or 0 According as n is even or n is odd.

If tan A=(1-cos B)/(sin B), then tan2A=tan B

2sin^(2)B+4cos(A+B)sin A sin B+cos2(A+B)=

(sin (4.1-2 beta) + (sin (4B-2A)) / (cos (4A-2B) + cos (4B-2A) = tan (A + B))

Prove that (1 + sin A) / (cos A) + (cos B) / (1-sin B) = (2sin A-2sin B) / (sin (AB) + cos A-cos B)

to prove that (cos A-cos B)^(2)+(sin A-sin B)^(2)=4sin^(2)((A-B)/(2))

Prove that (cos A-cos B)^(2)+(sin A-sin B)^(2)=4sin^(2)((A-B)/(2))

Prove that (sin (4A - 2B) + sin (4B - 2A))/(cos (4A - 2B) + cos (4B - 2A)) = tan (A + B)