Equation of motion of a body is `(dv)/(dt) = -4v + 8,` where v is the velocity in `ms^-1` and t is the time in second. Initial velocity of the particle was zero. Then,

The motion of a body is defined by (dv(t))/(dt) = 6-3 v(t) where v (t) is the velocity (in m/s ) of the body at time t (in seconds ). If the body was at rest at t= 0 , find its velocity (in m/s ) when the acceleration is half the initial value.

The motion of a particle moving along x-axis is represented by the equation (dv)/(dt)=6-3v , where v is in m/s and t is in second. If the particle is at rest at t = 0 , then

The motion of a particle moving along x-axis is represented by the equation (dv)/(dt)=6-3v , where v is in m/s and t is in second. If the particle is at rest at t = 0 , then

The motion of a body is given by the equation (dv)/(dt)=4-2v , where v is the speed in m/s and t in second. If the body was at rest at t = 0, then find (i) The magnitude of initial acceleration (ii) Speed of body as a function of time

The motion of a body is given by the equation (dv)/(dt)=4-2v , where v is the speed in m/s and t in second. If the body was at rest at t = 0, then find (i) The magnitude of initial acceleration (ii) Speed of body as a function of time

A body moves so that it follows the following relation (dv)/(dt)=-v^(2)+2v-1 where v is speed in m/s and t is time in second. If at t=0, v=0 then find the speed (in m/s) when acceleration in one fourth of its initial value.

The motion of a body is given by the equation dv//dt=6-3v , where v is in m//s. If the body was at rest at t=0 The speed varies with time as

A particle is moving in a straight line such that dv//dt=-lambdav , where v is the velocity and lambda is a constant. At t=0 , the particle is at the origin and moves with velocity v_(0) . Sketch the following graphs: (a) v-t (b) s-t (c ) v-s (d) log_(e)v v//s t