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If f : R-{-1}->R and f is differentiabl...

If `f : R-{-1}->R ` and f is differentiable function satisfies ` " f (x+f(y) +x f(y)) = y+f(x)+y.f(x)` for all x,y belongs to` R-{-1}` then find the value of `2010 [ 1 +f(2009)]`

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