A bullet of mass 0.25 kg is fired with velocity 302m/s into a block of wood of mass 37.5kg.It gets embedded into it. The block `m_(1)` is resting on a long block and the horizontal surface on which it is placed. The coefficient of friction between `m_(1)` and `m_(2)` is 0.5. Find the displacement of on and the common velocity of `m_(1)` and `m_(2)`. Mass `m^(2)`= 12.5kg.

A bullet of mass 0.25kg is fired with velocity 302m//s into a block of wood of mass m_1=37.5kg . It gets embedded into it. The block m_1 is resting on a long block m_2 and the horizontal surface on which it is placed is smooth. The coefficient of friction between m_1 and m_2 is 0.5 . Find the displacement of m_1 on m_2 and the common velocity of m_1 and m_2 . Mass m_2=1.25kg .

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A bullet of mass m moving horizontally with a velocity v strikes a block of wood of mass M and gets embedded in the block. The block is suspended from the ceiling by a massless string. The height to which block rises is

A bullet of mass m moving horizontally with a velocity v strikes a block of wood of mass M and gets embedded in the block. The block is suspended from the ceiling by a massless string. The height to which block rises is

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A block of mass m=5kg is resting on a rough horizontal surface for which the coefficient of friction is 0.2 . When a force F=40N is applied, the acceleration of the block will be (g=10m//s^(2)) .