अवकल समीकरण `"dy"/"dx"=(1+x^2)/(y+sin y)` को हल कीजिए ।

Solve (dy)/(dx)=(1+x^(2))/(y+sin y)

Find dy/dx if y = sin y)^(sin 2x)

(dy) / (dx) = (y) / (x) + sin ((y) / (x))

sin x(dy)/(dx)+y=y^(2)

If y^y=x sin y , then dy/dx =

If (dy)/(dx)= y sin 2x, y(0)=1 , then solution is

If sin y=x sin(y+a) and (dy)/(dx)=(A)/(1+x^(2)-2x cos a) then the value of A is

If y^y=x sin y , then (dy)/(dx) =

If x cos (a + y)=cos y then prove that [dy/dx = cos^2 (a+ y) /sin a] . Hence show that [sin a (d^2y /dx^2) + sin 2(a+ y) dy/dx =0] .