The average time between two successive collision of an electron is `3.64xx10^(-8)s`. Its mobility is

The average time interval between two successive collisions of electrons with the vibrating atom is

An ideal gas is enclosed in a cylinder at pressure of 2atm and temperature, 300K. The mean time between two successive collisions is 6xx10^(-8) s. If the pressure is doubled and temperature is increased to 500K, the mean time between two successive collisions will be close to:

An ideal gas is enclosed in a cylinder at pressure of 2 atm and temperature, 300 K.The men time between two successive collosions is 6xx10^(-8) s. If the pressure to 500K , the mean time between two successive collisions will be close to :

The resistivity of material of a wire is 2xx10^(-8) Omegam and the number of free electrons per unit volume is 9xx10^(28) per m^3 . Calculate the relaxation time which is defined as the average time interval between two successive collisions. Also calculate the mean free path of electron (distance covered by electron between two successive collisions) if the drift velocity of electrons is 1.7 xx10^(-4)m//s .

The distance travelled by a molecule between two successive collisions is called as

The distance travelled by a molecule between two successive collisions is called as

Calculate the mean free path for the collision of nitrogen molecules at 0^@C temperature at 1 standard atmosphere pressure. The mean time interval between two successive collisions = 1.9 times 10^-10 s, R=8.31 times 10^7 erg.mol^-1.K^-1 molecular mass of nitrogen =28.