" 2."(sin^(4)theta+cos^(4)theta)/(1-2sin^(2)theta cos^(2)theta)=1

Prove that (sin^(4)theta-cos^(4)theta)/(sin^(2)theta-cos^(2)theta)=1

Prove the following identities: 2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta)+1=0sin^(6)theta+cos^(6)theta+3sin^(2)theta cos^(2)theta=1(sin^(8)theta-cos^(8)theta)=(sin^(2)theta-cos^(2)theta)(1-2sin^(2)theta cos^(2)theta)

Prove that sin^(4) theta + cos^(4) theta = 1 - 2 sin^2 theta cos^(2) theta

sin^(4) theta + cos ^(4) theta + 2sin^(2) theta cos ^(2) theta has value 1.

If : sin^(4)theta+cos^(4)theta+sin^(2)theta*cos^(2)theta=1-u^(2), "then" : u=

sec^(2)theta-(sin^(2)theta-2sin^(4)theta)/(2cos^(4)theta-cos^(2)theta)=1

2(sin^(6) theta + cos^(6)theta) - 3(sin^(4)theta + cos^(4)theta)+ 1 = 0

The value for 2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta)+1 is

The value of (2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta))/(cos^(4)theta-sin^(4)theta-2cos^(2)theta) is :