f(x)={[(2^(x+2)-16)/(4^(x)-16)," if "x!=2],[k,quad " if "x=2]" at "x=2

If f(x)={(2^(x+2)-16)/(4^(x)-16), if x!=2,k if x=2 is continuous at x=2, find k

f(x)={(2^(x+2)-16)/(4^(x)-16),quad if x!=2 and k, if x=2 at x=2

f(x)={(2^(x+2)-16)/(4^(x)-16),quad if x!=2k,quad if x=2 is continuous at x=2, find k

If f(x)={(2^(x+2)-16)/(4^x-16) , if x!=2 , k if x=2 is continuous at x=2 , find k

find the value of k, so that the function f(x)={((2^(x+2)-16)/(4^(x)-16)", if "x!=2),(k", if "x=2):} is continuous at x=2.

f(x) ={{:((2^(x+2)-16)/(4^(x)-16), if x ne 2 ),(k, if x = 2):} , x = 2 .

If f(x)={(2^(x+2)-16)/(4^x-16),if x!=2k ,if f(x) is continuous a t x=2, find k

If f(x) ={{:((2^(x+2)-16)/(4^(x)-16), if x ne 2 ),(k, if x = 2):} , is 'conti nuous' at x = 2 . then find 'k'.

If the function f(x)=(2^(x+2)-16)/(4^(x)-16) for x!=2;-A for x=2 is continuous at x=2 then A