The equation of the normal to the hyperbola ` x^(2) -4y ^(2) =5 at (3,-1) ` is

A : The eqution of the normal to the hyperbola x^(2) -4y^(2) =5 at (3,-1) is 4x -3y = 15 R : The equation of the normal to the hyperbola (x^(2))/( a^(2))-(y^(2))/(b^(2)) =1 at (x_1,y_1) "is" ( a^(2)x)/( x_1) +(b^(2)y)/( y_1) =a^(2) +b^(2)

The equation of the normal to the hyperbola 3 x^(2)-y^(2)=3 at (2,-3) is

Find the equation of the normal to the hyperbola 3x^(2)-4y^(2)=12 at the point (x_(1),y_(1)) on it. Hence, show that the straight line x+y+7=0 is a normal to the hyperbola. Find the coordinates of the foot of the normal.

Find the equation of the normal to the hyperbola x^(2)=4y drawn at (2,3).

Find the equation of the normal to the hyperbola x^(2)-y^(2)=9 at the point p(5,4).

Find the equation of normal to the hyperbola x^(2)-9y^(2)=7 at point (4,1).

Find the equation of the normal at (1, 0) on the hyperbola x^(2) - 4y^(2) = 1

The equation of the normal to the hyperbola (x^(2))/(25) -(y^(2))/(9) =1 at the point theta = (pi)/(4) is

Find the equation of tangent to the hyperbola 3x^(2) - 4y^(2) = 8 at (2, - 1)