`(sin theta, cos theta)` and `(3,2)` lies on the same side of the line `x+y=1`, then `theta`lies between
(A) `(0,pi/2)`
(B) `(0,pi)`
(C) `(pi/4,pi/2)`
(D) `(0,pi/4)`

If the point (2costheta, 2sintheta), for theta in (0, 2pi) lies in the region between the lines x+y=1 and x-y=2 containing the origin then theta lies in (A) (0, pi/2)cup((3pi)/2, 2pi) (B) [0,pi] (C) (pi/2, (3pi)/2) (D) [pi/4, pi/2]

The range of values of theta epsilon [ 0, 2pi] for which (1+ sin theta, 1 + cos theta) lies inside the circle x^2 + y^2 = 1 , is : (A) (0, pi) (B) (5pi/4, 7pi/4) (C) (pi, 3pi/2) (D) (3pi/2, 2pi)

The range of values of theta epsilon [ 0, 2pi] for which (1+ sin theta, 1 + cos theta) lies inside the circle x^2 + y^2 = 1 , is : (A) (0, pi) (B) (5pi/4, 7pi/4) (C) (pi, 3pi/2) (D) (3pi/2, 2pi)

If pi < theta<(3pi)/2' then theta lies in

If sin theta=(21)/(29) , find the value of sec theta+tan theta , if theta lies between 0 and pi//2 :

If tan(pi cos theta) =cot(pi sin theta), 0 lt theta lt(3pi)/4 , then sin(theta+pi/4) =

For 0 cos^(-1)(sintheta) is true when theta belongs to (a) (pi/4,pi) (b) (pi,(3pi)/2) (c) (pi/4,(3pi)/4) (d) ((3pi)/4,2pi)

If 1+sin theta + sin^(2) theta + ...oo= 4+2sqrt(3), 0 lt theta lt pi and theta != pi/2 , then theta

If sin theta=(21)/(29) , prove that sectheta+tan theta=2(1)/(2) if theta lies between 0 and (pi)/(2) . What will be the value of the expression when theta lies (i) between (pi)/(2) and pi and (ii) between pi and (3pi)/(2) ?

If cos(sinx)=0, then x lies in (a) (pi/4,pi/2)uu(pi/2,\ pi) (b) (-pi/4,\ 0) (c) (pi,(3pi)/2) (d) null set