The density of the atmosphere at sea level is `1.29kg//m^(3)` . Assume that it does not change with altitude . Then how high would the atmosphere extended ? `(g=9.8ms^(-2))`

Explanation

atm pressure at sea surface ,
`P_(a) =1.01xx10^(5)Pa`
Density of atmosphere `rho=1.29kgm^(-3)`
Acceleration of gravity `g=9.8ms^(-2)`
`thereforehP_(a)=hrhog`
`thereforeh=(P_(a))/(rhog)`
`=(1.01xx10^(5))/(1.29xx9.8)`
`=0.07989xx10^(5)`
`=7989m`
`8km`
In reality the density of air decreases with height so does the value of g also .
The atmospheric pressure extends with decreasing pressure over 100 km.
Moreover , the sea level atmospheric pressure is not always 760 mm of Hg . A drop in the Hg level by 10 mm or more is a sign of an approaching strom.