Home
Class 11
PHYSICS
1 Pa = …… "dyne"//cm^(2)....

1 Pa = …… `"dyne"//cm^(2)`.

Text Solution

Verified by Experts

The correct Answer is:
1Pa `=(1N)/(m^(2))=(10^(5)"dyne")/(10^(4)cm^(2))=10("dyne")/(cm)`
Promotional Banner

Topper's Solved these Questions

  • MECHANICAL PROPERTIES OF FLUIDS

    KUMAR PRAKASHAN|Exercise SECTION -C (Objective Questions) (VSQs) Match Type Questions|6 Videos
  • MECHANICAL PROPERTIES OF FLUIDS

    KUMAR PRAKASHAN|Exercise SECTION -C (Objective Questions) (VSQs) Assertion and Reason Type Questions|7 Videos
  • MECHANICAL PROPERTIES OF FLUIDS

    KUMAR PRAKASHAN|Exercise SECTION -C (Objective Questions) (VSQs)|100 Videos
  • MACHANICAL PROPERTIES OF SOLIDS

    KUMAR PRAKASHAN|Exercise QUESTION PAPER|11 Videos
  • MOTION IN A STRAIGHT LINE

    KUMAR PRAKASHAN|Exercise QUESTION PAPER|11 Videos

Similar Questions

Explore conceptually related problems

An object of mass 5 kg is suspended by a copper wire of length 2 m and diameter 5 mm. Calculate the increase in the length of the wire. In order not to exceed the elastic limit, what should be the minimum diameter of the wire ? For copper, elastic limit =1.5 xx 10 ^(9) "dyne" //cm ^(2) , (Y) = 1.1 xx 10 ^(12) "dyne"//cm^(2).

0.1 Pa = ...... Nm^(-2) = ...... "dyne" cm^(-2).

1 bar = ……. Pa

Calculate the molar specific heat at constant volume . Given : specific heat of hydrogen at constant pressure is 6.85 "cal" mol^(-1) K^(-1) and density of hydrogen = 0.0899 "g" cm^(-3) . One mole of gas = 2.016g, J=4.2xx10^(7) "erg" cal^(-1) and 1 atmosphere = 10^(6) "dyne" cm^(-2) .

If an experiment to measure coefficient of viscosity radius of tube measured r = (0.100 +- 0.001) cm and length 1 = (50.0 +- 0.1) cm and volume of fluid coming out of capillary in unit time is V = (0.25 +-0.01) cm//^(2) . If pressure difference between end of tube is p = 10^(6) dyne/ cm^(2) , then by using Poeisullie's law V=(pi pr^(4))/(8 eta l) Find coefficient of viscosity.

Young's modulus of steel is 1.9 xx 10^(11)(N)/(m^(2)) . When expressed in ("dyne")/(cm^(2)) of it will be equal to (IN = 10^(5) "dyne" , 1 m^(2)=10^(4) cm^(2))

Two vertical glass plates 1 mm apart are dipped into water. How high will the water rise between the plates. If the surface tension of water is 70 dyne cm^(-1)

In a U-tube diamter of two limbs are 0.5 cm and 1 cm respectively and tube has filled with water (T=72"dyne"//cm ) then liquid level difference between two limbs will be

Diameters of the arms of a U tube are 10 mm and 1 mm . It is partially filled with water and it is held in a vertical plane . Find the difference in heights of water in both the arms . (Surface tension of water =70 dyne cm^(-1) angle of contact =0^(@).g=980cms^(-2))

Find the pressure in a bubble of radius 0.2 cm formed at the depth of 5cm from the free surface of water . The surface tension of water is 70 dyne cm^(-1) and its density is 1gcm^(-3) . Atmospheric pressure is 10^(6) dyne cm^(-2) .The gravitational acceleration is 980cms^(-2) .