A capillary tube of radus r is immersed in water and water rises in it to a height h. The mass of water in the capillary tube is 5g . Another capillary tube of radius 2r is immersed in water. The mass of water that will rise in this tube is …….

Options

A. `2.5g`
B. `5.0g`
C. 10 g
D. 20 g

Answer

c

Explanation

`h=(2Tcostheta)/(rrhog)`
Mass of water in the first tube ,
`m=pir^(2)hrho=pir^(2)xx((2Tcostheta)/(rrhog))xxdelta`
`=(2pirTcostheta)/(g)`
`thereforempropttr therefore(m.)/(m)=(2r)/(r)=2`
or `m.=2m=2xx5g=10g`