Water is flowing with velocity `4ms^(-1)` in a cylinder of diameter 8 cm .It is connectedto a pipe with it end tip of diameter 2cm . Calculate the velocity of water at this free end.

Options

A. `4ms^(-1)`
B. `8ms^(-1)`
C. `32ms^(-1)`
D. `64ms^(-1)`

Answer

d

Explanation

Here , `v_(1)=4ms^(-1),A_(1)=pir_(1)^(2)=16pixx10^(-4)m^(2)`
`A_(2)=pir_(2)^(2)=pixx10^(-4)m^(2)`
Now using equation ,
`A_(1)v_(1)=A_(2)v_(2)`
`v_(2)=(A_(1)v_(1))/(A_(2))=(16pixx10^(-4)xx4)/(pixx10^(-4))=64ms^(-1)`
Hence the velocity of water at free end is `v_(2)=64ms^(-1)`