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Neglecting the density of air ,the termi...

Neglecting the density of air ,the terminal velocity obtained by a raindrop of radius 0.3 mm falling through air of viscosity `1.8xx10^(-5)Nsm^(-2)` will be ….

A

`10.9ms^(-1)`

B

`7.48ms^(-1)`

C

`3.7ms^(-1)`

D

`12.8ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
a

`r=0.3mm=3xx10^(-4)m`
`eta=1.8xx10^(-5)Nms^(-2)`
Terminal velocity `v_(t)=(?)`
`v_(t)=(2)/(9)(r^(2)g(rho-rho_(o)))/(eta)`
`rho` = density of water `=10^(3)kg//m^(3)`
`rho_(o)`=neglecting air density
`v_(t)=(2)/(9)((9xx10^(-8))(9.8)(10^(3)))/(1.8xx10^(-5))`
`=10.88`
`v_(t)=10.9m//s`
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