Density of ice is `rho` and that of water is `sigma` .What will be from following decrease in volume when a mass M of ice melts ?

Options

A. `(M)/(sigma-rho)`
B. `(sigma-rho)/(M)`
C. `M[(1)/(rho)-(1)/(sigma)]`
D. `(1)/(M)[(1)/(rho)-(1)/(sigma)]`

Answer

c

Explanation

Volume of ice `V_(1)=(M)/(rho)`
Volume of water `V_(2)=(M)/(sigma)`
If `V_(1)gtV_(2)` , volume decreases for melting of ice .
Decrease in volume `=V_(1)-V_(2)=(M)/(rho)=(M)/(sigma)`
`=M[(1)/(rho)-(1)/(sigma)]`