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Under a constant pressure, the rate of f...

Under a constant pressure, the rate of flow of liquid through capillary is V. if the length of capillary is doubled and the diameter of the bore is halved, the rate of flow would be ……

A

`(V)/(4)`

B

16 V

C

`(V)/(8)`

D

`(V)/(32)`

Text Solution

Verified by Experts

The correct Answer is:
d
According to Poiseille.s equation,
Rate of flow `V=(piPr^(4))/(8etal)`
Diameter `d.=(d)/(2)thereforer.=(r)/(2)`
and `l=2l`
`V.=(pip(r.)^(4))/(8etal)`
`thereforeV.=(pip((r)/(2))^(4))/(8eta(2l))`
`thereforeV.(pip((r^(4))/(16)))/(2(8etal))`
`thereforeV.=(pipr^(4))/(32(8etal))`
`thereforeV.=(V)/(32)`
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